Data Interpretation Questions play an important role in all the competitive exams, so we are providing here the most expected Data Interpretation Set Which will help you to boost your Data Interpretation skills. All the aspirants who are preparing for bank examinations or other competitive examinations can take benefits from this set.
The table shows the distance travelled by five different boats upstream and downstream in same time and the line chart shows the speed of stream.
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Question 1 of 5
1. Question
Find the ratio of the speed of boats A in still water to the speed of boats B in still water.
Correct
To find the speed of the boat A in still water:
[120/(x18)] = [220/(x+18)]
120x+ 2160=220x3960
x=61.2 km/hr
To find the speed of the boat B in still water:
[120/(x12)] = [165/(x+12)]
120x +1440= 165x1980
x=76 km/hr
Required ratio= 61.2:76 =612:760 = 153: 190Incorrect
To find the speed of the boat A in still water:
[120/(x18)] = [220/(x+18)]
120x+ 2160=220x3960
x=61.2 km/hr
To find the speed of the boat B in still water:
[120/(x12)] = [165/(x+12)]
120x +1440= 165x1980
x=76 km/hr
Required ratio= 61.2:76 =612:760 = 153: 190 
Question 2 of 5
2. Question
The speeds of the boat M in still water is 46 km/hr less than the speed of the boat B in still water. If the boat M travels 126 km distance downstream and 81 km distance upstream in 7 hours 30 minutes, then what is the speed of stream of boat M?
Correct
From above questions, we know that speed of the boat
B in still water=76 km/hr
Then speed of the boat M in still water=7646=30 km/hr
Let the speed of the stream of the boat M be x km/hr
Then, [126/ (30+x)] + [81/(30x)]=15/2
After solving, we get, x= 6 and 12 Thus, speed of the stream= 12 km/hrIncorrect
From above questions, we know that speed of the boat
B in still water=76 km/hr
Then speed of the boat M in still water=7646=30 km/hr
Let the speed of the stream of the boat M be x km/hr
Then, [126/ (30+x)] + [81/(30x)]=15/2
After solving, we get, x= 6 and 12 Thus, speed of the stream= 12 km/hr 
Question 3 of 5
3. Question
If the speed of the boat A in still water is increased by 40% and the speed of stream is increased by 90%, then find the time taken by boat A to cover the upstream distance of 378 km.
Correct
Speed of the boat A in still water:
[120/(x18)] = [220/(x+18)]
120x+ 2160=220x3960
x=61.2 km/hr
After increasing, the speed of the boat A in still water=61.2*140/100=85.68 km/hr
And speed of the stream=18*190/100= 34.2 km/h/r
Thus, required time= 378/ (85.6834.2)=7.3 hoursIncorrect
Speed of the boat A in still water:
[120/(x18)] = [220/(x+18)]
120x+ 2160=220x3960
x=61.2 km/hr
After increasing, the speed of the boat A in still water=61.2*140/100=85.68 km/hr
And speed of the stream=18*190/100= 34.2 km/h/r
Thus, required time= 378/ (85.6834.2)=7.3 hours 
Question 4 of 5
4. Question
The speed of boat B and boat D in still water together is approximately how much percentage more than the speed of stream of the same boats together?
Correct
To find the speed of boat B in still water:
We know that Time= distance/ speed
Then, [120/(x12)] = [165/(x+12)]
120x +1440= 165x1980
x=76 km/hr
To find the speed of the boat D in still water:
[200/(x10)] = [320/(x+10)]
200x +2000= 320x3200
x=43.33 km/hr
Then the speed of boat B and boat D in still water together=76+43.33= 119.33 km/hr = 119 km/hr
And, speed of stream of the boat B and boat D together=12+10= 22 km/hr
Then Required percentage= [(11922)/22]*100
= 441%Incorrect
To find the speed of boat B in still water:
We know that Time= distance/ speed
Then, [120/(x12)] = [165/(x+12)]
120x +1440= 165x1980
x=76 km/hr
To find the speed of the boat D in still water:
[200/(x10)] = [320/(x+10)]
200x +2000= 320x3200
x=43.33 km/hr
Then the speed of boat B and boat D in still water together=76+43.33= 119.33 km/hr = 119 km/hr
And, speed of stream of the boat B and boat D together=12+10= 22 km/hr
Then Required percentage= [(11922)/22]*100
= 441% 
Question 5 of 5
5. Question
The distance between point P and point Q is 480 km. If the boat E travels from point P and point Q upstream and downstream with the speed of 140km/hr in still water, then what is the total time taken by the boat E to cover the total distance?
Correct
We know that, time=Distance/Speed
Then, Required time= [480/(14020)]+[480/(140+20)]
=4+3
= 7 hoursIncorrect
We know that, time=Distance/Speed
Then, Required time= [480/(14020)]+[480/(140+20)]
=4+3
= 7 hours
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