Data Interpretation Questions play an important role in all the competitive exams, so we are providing here the most expected Data Interpretation Set Which will help you to boost your Data Interpretation skills. All the aspirants who are preparing for bank examinations or other competitive examinations can take benefits from this set.
Directions (1 – 5): Study the given Radar Chart and the Pie chart carefully. Time taken by the pipes to fill a tank/cistern (hours/minutes)
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You have reached 0 of 0 points, (0) Three pipes R, A and B can fill the tank. R can fill the tank 5 minutes less than that of B. If all the pipes are opened together and pipe B is turned off 5 minutes before the tank is filled. Then find the time in which the tank will full. Let total time taken by the pipes is X hrs, Let total time taken by the pipes is X hrs, Two pipes I and J are opened simultaneously and it is found that due to leakage in the bottom of the tank it took 48 minutes’ excess time to fill the cistern. When is the cistern full, in what time will the leak empty it? Work done by the two pipes in 1 hour = (1/12) + (1/18) Work done by the two pipes in 1 hour = (1/12) + (1/18) A waste pipe, W can carry off 12 litre of water per minute. If all the pipes M, N and W, are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank. Let the waste pipe take ‘X’ time to empty the tank. Let the waste pipe take ‘X’ time to empty the tank. Two pipes K, and L are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water supplied by the pipe leaks out. What is the total time to fill the tank? (1/15 + 1/30) *T1 = 1/3, T1 = 10/3 minutes (1/15 + 1/30) *T1 = 1/3, T1 = 10/3 minutes Three pipes N, C and D can fill a tank. If pipe N is opened all the time and pipe C and D are (1/12 + 1/15) + (1/12 + 1/20) = 17/60 (in 2 hrs this (1/12 + 1/15) + (1/12 + 1/20) = 17/60 (in 2 hrs thisQuiz-summary
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1. Question
(1/5 + 1/10 + 1/15) *(X – 5) + (1/5 + 1/15) *5 = 45/11
(1/5 + 1/10 + 1/15) *(X – 5) + (1/5 + 1/15) *5 = 45/11
2. Question
= (15/108).
Time taken by these pipes to fill the tank = (108/15) hrs
= 7 hours 12 min.
Due to leakage, time taken = 7 hours 12 min + 48 min
= 8 hours
Work done by two pipes and leak in 1 hour = 1/8.
Work done by the leak in 1 hour = (15/108) -(1/8) =
(1/72).
Leak will empty the full cistern in 72 hours.
= (15/108).
Time taken by these pipes to fill the tank = (108/15) hrs
= 7 hours 12 min.
Due to leakage, time taken = 7 hours 12 min + 48 min
= 8 hours
Work done by two pipes and leak in 1 hour = 1/8.
Work done by the leak in 1 hour = (15/108) -(1/8) =
(1/72).
Leak will empty the full cistern in 72 hours.
3. Question
(1/10 + 1/12 – 1/X) *60 = -1
we will get X = 5 min
so capacity = 5*12 = 60ltr
(1/10 + 1/12 – 1/X) *60 = -1
we will get X = 5 min
so capacity = 5*12 = 60ltr
4. Question
Now after leak is developed,
[(1/15 + 1/30) – (1/3) *(1/15 + 1/30)] *T2 = 2/3
T2 = 10 minutes.
So total time = 10 + 10/3 = 40/3 minutes
Now after leak is developed,
[(1/15 + 1/30) – (1/3) *(1/15 + 1/30)] *T2 = 2/3
T2 = 10 minutes.
So total time = 10 + 10/3 = 40/3 minutes
5. Question
opened for one hour alternatively. The tank will be full in
much tank is filled)
so in 6 hrs 51/60 is filled.
Remaining, 9/60 = (1/12 + 1/15) *T, so T = 1hr
so total = 6 + 1 = 7 hr
much tank is filled)
so in 6 hrs 51/60 is filled.
Remaining, 9/60 = (1/12 + 1/15) *T, so T = 1hr
so total = 6 + 1 = 7 hr
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can you provide these study material in Hindi language ……there is language problem….
Please, provide more di set for practise.
Your puzzle quality is very good.
we will work on DI Sets soon
whether the answer for the question “three pipes r a b …….” is correct ?