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Direction (1 â€“ 5): Study the following data carefully and answer the questions:
There are five boats A, B, C, D and E that are running in the same river. First pie chart
given below shows the distribution (degree) of upstream time taken by five boats and
second pie chart given below shows the per cent distribution of upstream distance travelled
by the five boats in the time mentioned in the first pie chart.
Sum of the first pie chart is 12 hours while that of the second pie chart is 400 km.
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Question 1 of 4
1. Question
Boat C starts travelling in downstream and it has to travel 130 km. After
travelling for 48 minutes engine of the boat stops working. Now, the boat starts
floating with the speed of stream for â€˜xâ€™ minutes. After this the speed of boat in
still water is increases by 20% to cover the total distance in estimated time, then
what is the value of â€˜xâ€™?Correct
Estimated time to cover 130 km in downstream by boat C = 130/65 = 2 hours
Downstream distance travelled in 48 minutes = 65 * (48/60) = 52 km
Distance travelled in â€˜xâ€™ minutes along with speed of stream = 10 * (x/60) = (x/6) km
Remaining distance = 130 â€“ [52 + (x/6)] = [(468 â€“ x)/6] km
Remaining time = 120 â€“ 48 â€“ x = (72 â€“ x) minutes = [(72 â€“ x)/60] hours
Downstream speed of boat when its speed water in increase by 20% = (120% of 55) + 10
= 76 km/h
According to the question:
[(468 â€“ x)/6] Ã· (1/76) = (72 â€“ x)/60
4680 â€“ 10x = 5472 â€“ 76x
66x = 792
x = 12 minutesIncorrect
Estimated time to cover 130 km in downstream by boat C = 130/65 = 2 hours
Downstream distance travelled in 48 minutes = 65 * (48/60) = 52 km
Distance travelled in â€˜xâ€™ minutes along with speed of stream = 10 * (x/60) = (x/6) km
Remaining distance = 130 â€“ [52 + (x/6)] = [(468 â€“ x)/6] km
Remaining time = 120 â€“ 48 â€“ x = (72 â€“ x) minutes = [(72 â€“ x)/60] hours
Downstream speed of boat when its speed water in increase by 20% = (120% of 55) + 10
= 76 km/h
According to the question:
[(468 â€“ x)/6] Ã· (1/76) = (72 â€“ x)/60
4680 â€“ 10x = 5472 â€“ 76x
66x = 792
x = 12 minutes 
Question 2 of 4
2. Question
Total time taken by boat A to go â€˜3xâ€™ km in upstream and â€˜xâ€™ km in downstream
is same as the total time taken by boat B to go â€˜2xâ€™ km in upstream and â€˜x + 12â€™
km in downstream, then what is the value of â€˜xâ€™?Correct
Total time taken by boat A to go â€˜3xâ€™ km in upstream and â€˜xâ€™ km in downstream = (3x/30)
+ (x/50) = 0.1x + 0.02x = 0.12x
Total time taken by boat B to go â€˜2xâ€™ km in upstream and â€˜x + 12â€™ km in downstream =
(2x/25) + [(x + 12)/45] = 0.08x + [(x + 12)/45]
According to the question:
0.12x = 0.08x + [(x + 12)/45]
5.4x = 3.6x + x + 12
0.8x = 12
x = 15 kmIncorrect
Total time taken by boat A to go â€˜3xâ€™ km in upstream and â€˜xâ€™ km in downstream = (3x/30)
+ (x/50) = 0.1x + 0.02x = 0.12x
Total time taken by boat B to go â€˜2xâ€™ km in upstream and â€˜x + 12â€™ km in downstream =
(2x/25) + [(x + 12)/45] = 0.08x + [(x + 12)/45]
According to the question:
0.12x = 0.08x + [(x + 12)/45]
5.4x = 3.6x + x + 12
0.8x = 12
x = 15 km 
Question 3 of 4
3. Question
Boat D start from the bank of river in downstream and after travelling for 12
minutes a ship start from the bank and catches the boat D after travelling for 28
minutes. After travelling for how much time (in minutes) the ship will catch the
boat if the same scenario will happen in upstream?Correct
Downstream speed travelled by boat D in 12 minutes = 70 * (12/60) = 14 km
Let the downstream speed of ship = â€˜xâ€™ km/h
Effective speed of boat and ship when travelling same direction = (x â€“ 70) km/h
According to the question:
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14 = (x â€“ 70) * (28/60)
(x â€“ 70) = 30
x = 100 km/h
Upstream speed of ship = 100 â€“ 10 â€“ 10 = 80 km/h
Effective speed of boat and ship when travelling same direction = (100 â€“ 70) = 30 km/h
Upstream speed travelled by boat D in 12 minutes = 50 * (12/60) = 10 km
Required time taken = (10/30) * 60 = 20 minutesIncorrect
Downstream speed travelled by boat D in 12 minutes = 70 * (12/60) = 14 km
Let the downstream speed of ship = â€˜xâ€™ km/h
Effective speed of boat and ship when travelling same direction = (x â€“ 70) km/h
According to the question:
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14 = (x â€“ 70) * (28/60)
(x â€“ 70) = 30
x = 100 km/h
Upstream speed of ship = 100 â€“ 10 â€“ 10 = 80 km/h
Effective speed of boat and ship when travelling same direction = (100 â€“ 70) = 30 km/h
Upstream speed travelled by boat D in 12 minutes = 50 * (12/60) = 10 km
Required time taken = (10/30) * 60 = 20 minutes 
Question 4 of 4
4. Question
A race between boats A and E is conducted, then what is the ratio of distance by which boat E will beat boat A when the race is conducting in upstream to the distance by which boat E will beat boat Awhen the race is conducting in downstream and length of the race is 11.55 km?
Correct
Time taken by E to complete the race in upstream = (11.55/35) = 0.33 hours
Upstream distance covers by boat A in 0.33 hours = 0.33 * 30 = 9.9 km
Distance by which boat E will beat boat A when the race is conducting in upstream = 11.55 â€“ 9.9 = 1.65 km
Time taken by E to complete the race in downstream = (11.55/55) = 0.21 hours
Downstream distance covers by boat A in 0.21 hours = 0.21 * 50 = 10.5 km
Distance by which boat E will beat boat A when the race is conducting in downstream = 11.55 â€“ 10.5 = 1.05 km
Required ratio = 1.65: 1.05 = 11: 7Incorrect
Time taken by E to complete the race in upstream = (11.55/35) = 0.33 hours
Upstream distance covers by boat A in 0.33 hours = 0.33 * 30 = 9.9 km
Distance by which boat E will beat boat A when the race is conducting in upstream = 11.55 â€“ 9.9 = 1.65 km
Time taken by E to complete the race in downstream = (11.55/55) = 0.21 hours
Downstream distance covers by boat A in 0.21 hours = 0.21 * 50 = 10.5 km
Distance by which boat E will beat boat A when the race is conducting in downstream = 11.55 â€“ 10.5 = 1.05 km
Required ratio = 1.65: 1.05 = 11: 7
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i didnt understood how downstream speed has taken please explain it